Hierbij heb ik probleem met mijn script kan iemand mij helpen?
PHP
<?
include ('header.php');
?>
<div id='Content'>
<div class="content">
<div class="titel">Standen Overzicht</div>
<p>
<?PHP
$tabel ="TMD1_standen";
$opdracht = "SELECT * FROM $tabel";
$result = mysql_query($opdracht);
if($_GET['standen']){
$query = mysql_query("SELECT `id`, `stand`, `clubnr1`, `clubnr2` FROM `medailes`
WHERE `id` = '$id' LIMIT 1");
while($row = mysql_fetch_object($query)){
?>
<table>
<tr>
<td width="10%"><b>ID Nummer</b></td>
<td width="10%"><b>Stand</b></td>
<td width="10%"><b>Club Thuis</b></td>
<td width="10%"><b>Club Uit</b></td>
<td width="10%"><b>Gele kaarten</b></td>
<td width="10%"><b>Rode kaarten</b></td>
</tr>
<tr onmouseover="this.bgColor='<?= $config['tabel_bg']; ?>'" onmouseout="this.bgColor=''">
<td> <?=$row->id;?> </td>
<td> <?=$row->stand;?> </td>
<td> <?=$row->clubnr1;?> </td>.
<td> <?=$row->clubnr2;?> </td>
</tr>
</table>
</p>
</div>
</div>
<?PHP
include ('footer.php');
?>
Toon Meer
De foutmelding is:
Parse error: syntax error, unexpected $end in D:\studenten_website\website\68645\TMD1\WEBSITE\standen_overzicht.php on line 54
Ik kom er zelf niet uit.